Question

17. Based on the group valency suggest the formulae for
a) Oxides of group 1 elements
b) Halides of group 13 elements
c) Hydrides of group 15 elements​

Answer 1

Answer:

a)Group 1 metals are very reactive with oxygen and must be kept away from oxygen in order to not get oxidized. These alkali metals rapidly react with oxygen to produce several different ionic oxides. Oxides: O2- , peroxides: O22- , super oxide: O2-

b)Boron trihalide(BX3), Aluminium trihalide(AlX3), Gallium trihalide(GaX3), Indium trihalide(InX3), Thallium monhalide(TlX). The stability of +3 charge decrease down the group and stability of +1 charge increases down group 13 due to Inert Pair Effect and hence Thallium exists in +1 state

c)E can be nitrogen, phosphorus, arsenic, antimony or bismuth. Stability: The stability of hydrides decreases from ammonia to bismuthine. This is because the central atom E increases in size down the group.

#mis_naming_lovex

Answer 2

a.$A_2O$

b.$AB_3$

c.$EH_3$

Step-by-step explanation:

a.Valency of group 1 element=+1

Valency of oxygen=-2

Therefore , the formula of oxides of group of 1 element is given by

$A_2O$

Where A=Element of group 1

For example , $Na_2O$

Where Na=Element of group 1

b.Valency of group 13 elements=+3

Valency of halogen family=-1

Therefore, the formula of halides of group 13 elements is given by

$AB_3$

Where A=Element of group 13 element

B=Halogen member

For example :

$AlCl_3$

Where Al=Element of group 13

Cl=Element of halogen family

c.Valency of group 15 elements=+5 or-3

Valency of hydrogen=+1

But it form trihyride

Therefore, the formula of hydrides of group 15 elements is given by

$EH_3$

Where E=Element of group 15 elements

For example:$NH_3$