17. Calculate the speed of electron revolving around the nucleus of a hydrogen atom in order that it
may not be pulled into the nucleus by electrostatic attraction.
Answers
Answered by
1
Here in this case the speed of the electron is ,
v=2πr1TNow , r1=0⋅0529×10−9 mT=1⋅519×10−16 sSo the speed is , v=2π×0⋅0529×10−91⋅519×10−16 =2⋅19×106 m/s
Answered by
1
The speed of the electron revolving around the nucleus of hydrogen atom in order that it may not be pulled into the nucleus by electrostatic attraction is
Explanation:
Data
Let us take centripetal force is equal to the electrostatic force
Equate (1) and (2)
Substitute the respective values in above equation.
Therefore the speed required by an electron is , when an electron revolving around the nucleus of a hydrogen atom in order that it may not be pulled into the nucleus by electrostatic attraction.
To Learn More
1) What is an electrostatic force? Why is it called non-contact force?
https://brainly.in/question/1166816
2) If the centripetal force is of the form m^a × v^b × r^c, find the values of a, b and c.
https://brainly.in/question/3802346
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