Question

17.. class bank
{
double bal=2000.0; String s="Anu";
String accout_type="SB";
public bank()
{
System.out.println(s + "\t"+ bal);
}
public static void main()
{
bank obj = new bank();
}
What is the output of the given program?

A) Error
B) Anu SB 2000
C) Anu SB 2000
D) Anu 2000.0​

Answer 1

Answer:

Option D: Anu 2000.0

Códe :-

class bank

{

double bal=2000.0; String s="Anu";

String accout_type="SB";

public bank()

{

System.out.println(s + "\t"+ bal);

}

public static void main()

{

bank obj = new bank();

}

}

When the above códe runs, control will first execute main(). In main() an object of a class is being created using new operator and at the same time, a constructor (bank()) is being called. So the control will now execute the constructor. In constructor, value of s which is "Anu" and value of bal which is 2000.0 is printed. The control then returns to main() where the program finally terminates.

Extra:-

• In the print statement, \t escape sequence is present which is used to insert a tab in terminal window. So the output will be,

$\boxed{ \tt Anu \: \: \: \: \: 2000.0}$

• Constructor is always called during object creation.
• Constructor name is same as the class name.
• Escape Sequences are always given in double quotes