Question

17.Find all the zeroes of f(x) = x2 − 23.

Answer 1

Step-by-step explanation:

Given polynomial is x2−5.

Let the zeros be α,β. ( α>β)

x2−5=0⇒x2=5⇒x=±5.

α=5 ,β=−5.

So, α+β=0,αβ=−5.

The coefficient of x is zero ⇒α+β=0.

Constant = αβ=−5.

hope my answer is correct✅