Question

17. Find the 25th term of an arithmetic progression 2, 6, 10, 14, ...​

Answer 1

Step-by-step explanation:

a25=a+(n-l)d

d=6-2

d=4

a25=2+(25-1)4

a25=2+(24)(4)

a25=98

Answer 2

The 25th term of an arithmetic progression 2, 6, 10, 14, . . . is 98

Given :

The arithmetic progression 2, 6, 10, 14, . . .

To find :

The 25th term of an arithmetic progression

Formula :

The nth term of an arithmetic progression is given by

Aₙ = a + ( n - 1 ) d

Where a = First term and d = Common Difference

Solution :

Step 1 of 2 :

Find common difference

Here the given arithmetic progression is

2, 6, 10, 14, . . .

First term = a = 2

Common Difference = d = 6 - 2 = 4

Step 2 of 2 :

Find 25th term of the arithmetic progression

25th term of the arithmetic progression

= a + ( 25 - 1 )d

= a + 24d

= 2 + ( 24 × 4 )

= 2 + 96

= 98

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ Find the smallest term of geometric progression 3,5,25/3 that exceeds 100.

https://brainly.in/question/26328002

3. 8 GM's are inserted between 3 and 4

then the product of 8 GM's

https://brainly.in/question/29050188