Question

17. Find the focus, equation of directrix and length of latus lactum of x2 = -9y​

Answer 1

Answer:

y2−6y=−8x−1

y2−6y+9=−8x+1+9 (Adding 9 on both sides)

(y−3)2=−8x+8

(y−3)2=−8(x−1)

This is of the form Y2=−8X where X=x−1 and Y=y−3

4a=8⇒a=48=2 This type is open leftward