Math, asked by mishmistu, 8 months ago

17. Find the least number which when divided by 35, 56 and 91 leaves the
same remainder 7 in each case.

Answers

Answered by nakulathul

4

Answer:

Step-by-step explanation:

3647

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

Answered by Anonymous

3

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