Question

17. Find the nature of roots of the equation, if real root exist find them by
quadratic formula x^2-3x-10=0
​

Answer 1

Step-by-step explanation:

Discriminant (D) = b² – 4ac.

Discriminant(D) = b² – 4ac.

Hence, real roots exist & they are equal to each other.

roots will be –b/2a and –b/2a.

Discriminant (D)= b² – 4ac.

Hence, two distinct real roots exist for this equation.

x= -b/2a + √D/2a & x= -b/2a - √D/2a.

Answer 2

Answer:

roots are x=5 (or) -2

Step-by-step explanation:

to find they have real roots follow the formula

b²-4ac=∆

∆<0(no real root)

∆=0(equal roots)

∆>0(different real roots)

-3²-4(1)(-10)=9+40=49=∆(∆>0)

it means this has unequal real roots

x²-3x-10=(x-5) (x+2)

x=5(or) -2