Question

17. Find the number of
students among whom
1001 pens and 910 pencils
can be equally
distributed? *
​

Answer 1

Total pens=1001

Total pencils=910

we need to find maximum no.of students among whom 1001 pens and 910 pencils can be distributed in such a way that each students get same no.of pens and pencils.

Then we need to find HCF of 1001 and 910

Prime factorization of,

1001=7×11×13

910=2×5×7×13

HCF=product of commom prime factor of least power

HCF=7×13=91

Here HCF of 1001 and 910 is 91.

Hence among 91 students 1001 pens and 910 pencils can be distributed such that each student get same no.of pens and pencils.

Answer 2

Answer:

$910 + 1001 \div 2$