Question

17. Find the sum and product of zeroes of
p(x) = 2(x^2 - 3) + X.​

Answer 1

Answer:

sum of zeroes is -1/2

product of zeroes is -3

Answer 2

Answer:

$p(x) = 2 {x}^{2} + x - 6 \\ compare \: \: with \: \: a {x}^{2} + bx + c \\ a = 2 \: \: \: \: \: \: \: \: \: b = 1 \: \: \: \: \: \: \: c = - 6 \\ now \\ \\ \alpha + \beta = \frac{ -b }{a} = \frac{ - 1}{2} \\ \\ \alpha \beta = \frac{c}{a} = \frac{ - 6}{2} = - 3$