17. Find the value of n when:
(i) 52n x53 = (5) power 9
(ii) 8x2n+2 = 32
(iii) 62n+1 = 36 =6
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(1)
52n×53=59
Apply law of exponents xa×xb=xa+b
52n+3=59
⇒2n+3=9
2n=9−3
2n=6
n=3
(2)
8×2n+2=32
23×2n+2=25
Apply law of exponents xa×xb=xa+b
23+n+2=25
2n+5=25
⇒n+5=5
n=5−5
n=0
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