Question

17. Find the value of n when:
(i) 52n x53 = (5) power 9
(ii) 8x2n+2 = 32
(iii) 62n+1 = 36 =6​

Answer 1

Answer:

Answer

(1)

52n×53=59

Apply law of exponents xa×xb=xa+b

52n+3=59

⇒2n+3=9

2n=9−3

2n=6

n=3

(2)

8×2n+2=32

23×2n+2=25

Apply law of exponents xa×xb=xa+b

23+n+2=25

2n+5=25

⇒n+5=5

n=5−5

n=0

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