Question

17. Find the value of x:-
a)
(-3)^x (-3) ^2x = (-3)^-9​

Answer 1

Answer:

(-3)

Step-by-step explanation:

$( { - 3})^{x} \times ( { - 3})^{2x} = ({ - 3})^{ - 9}$

According to the formula,

${a}^{x} \times {a}^{y} = {a}^{x + y} \\ = > ({ - 3})^{x + 2x} = ( { - 3})^{ - 9}$

When bases are same, powers are equal.

$= > x + 2x = - 9 \\ = > 3x = - 9 \\ = > x = \frac{ - 9}{3} \\ = > x = (- 3)$

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Answer 2

Answer:

(-3)^x*(-3)^2x =(-3)^-9

= - 3^2x+x = - 3^-9

=-3^3x =-3^-9

=3x = - 9

= x =-3