Question

17. Find the value of x , if 2^×=1/32​

Answer 1

Answer:

We are given:

2

x

=

1

32

=

1

2

5

=

2

−

5

So the unique Real solution is

x

=

−

5

Complex solutions

e

2

π

i

=

1

So:

2

x

=

2

−

5

⋅

e

2

k

π

i

=

2

−

5

⋅

2

2

k

π

ln

(

2

)

i

=

2

−

5

+

2

k

π

ln

(

2

)

i

So

x

=

−

5

+

2

k

π

ln

(

2

)

i

for any integer

k

Step-by-step explanation:

Pls Mark Brainliest

Answer 2

Answer:

x = -5

Step-by-step explanation:

2^x = 1/32

2^x = 1/2^5

2^x = 2^-5

bases are same exponents must be equal

x = -5