Question

17. Find the zeroes of the polynomial 8x4 - 4.​

Answer 1

Answer:

$given \: that \\ p(x) = 8 {x}^{4} - 4 \\ where \: p(x) = 0 \\ 8 {x}^{4} - 4 = 0 \\ 8 {x}^{4} = 4 \\ {x}^{4} = \frac{4}{8} = \frac{1}{2} \\ x = \frac{ + }{} \sqrt[4]{ \frac{1}{2} }$