Chemistry, asked by simranbodh26, 1 month ago

17 g of NH 3 is mixed with the same mass NH 4 Cl formed is (a) 17.00g (6) 34.00g (1) 53.50g (d) 24.92 g​

Answers

Answered by mithuanushtha
3

Answer:

HCl(g)+NH

3

(g)−NH

4

Cl(s)

If 3.0 moles of HCl gas and 3 moles of NH

3

gas. each measured at 20

o

C and 1.0 atmosphere pressure, are allowed to react completely according to the equation above, the final mixture will contain

A

3 moles of solid NH

4

Cl only

B

5 moles of solid NH

4

Cl only

C

3 moles of solid NH

4

Cl+2 moles of NH

3

gas

D

3 moles of solid NH

4

Cl+2 moles of HCl gas

E

2 moles of HCl gas, 4 moles of NH

3

gas. and 1 mole of solid NH

4

Cl

Answered by AtharvSena
1

as the question is incomplete the complete question may be this (17 g of NH 3 is mixed with the same mass of HCl then the mass of NH 4 Cl formed is ?)

(a) 17.00g

17 g of NH 3 is mixed with the 17g HCl then the mass of NH_{4}Cl formed is (a) 17.00g

HCl (g)+ NH_{3}(g)---- > NH_{4}Cl(s)

This is a balanced equation for the formation of ammonium chloride.

If we mix same amount of hydrogen chloride and ammonia we get same amount of ammonium chloride.

so, the correct option is (a) 17.00g

#SPJ2

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