17.
Given that y=sin 3x +4/3 cos3x. What is the
maximum rate of change in y with respect to x ?
Answers
Answered by
6
Answer:
dy/dx=3cos3x-4sin3x
Step-by-step explanation:
by putting the formula
d/dx(sinx)=cosx
d/dx(cosx)=-sinx
I hope it will help you.
sonu7170:
thanks mate.
Answered by
8
Answer:
As in the question it is given to find the maximum change in y with respect to x that means the double differentiation of the function y must be < 0.
First we have to find the differentiation of the function y which is:-
dy/dx = d/dx(sin3x) + d/dx(4/3cos3x).
dy/dx = 3cos3x + 4/3{-3sin3x}.
dy/dx = 3cos3x - 4sin3x.
Now to find the maximum value we need to find x which we can find by taking dy/dx = 0
3cos3x = 4sin3x.
tanx= 3/4.
So, x= tan^-1(0.75) = 36.
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