Math, asked by risingstar2005, 6 months ago

17) How many solutions are there for the following pair of equations? Justify.
2x - 3y - 1=0: 4x - 6y - 2 = 0​

Answers

Answered by student6685
5

Step-by-step explanation:

for first equation:- 2x-3y-1=0

if x=2/2

y=1/3

substitute with the following equation

2(2/2) - 3(1/3) - 1

2-1-1=0

for second equation:- 4x-6y-2

if x=4/4

y=(2/6)

substitute with the following equation

4(4/4) - 6(2/6) -2

4-(2)-2=0

we can have only one solution

Hope it is helpful

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