Question

17) If 1/3 is a
a zero of the polynomial 3 x ² + bx+ 5 then find b
​

Answer 1

Answer:

b=-16

Step-by-step explanation:

➡️p(1/3)=3(1/3)^2+b(1/3)+5=0

= 3/9+b/3+5/1=0

= 1/3+b/3+5/1=0(3/9 cut by 1/3)

= 1+b+15/3=0

= 1+b+15=0×3

= 1+b+15=0

= b+16=0

= b=-16

THIS IS YOUR ANSWER MY FRIEND...

Answer 2

Answer:

The value of b is -16

Step-by-step explanation:

If 1/3 is a zero of the polynomial 3x² + bx + 5

∴ x= 1/3

(Substituting the value of x , we get :- )

3 X 1/9 + 1/3b + 5 = 0

⇒ 1/3 + 1/3b = -5

⇒1/3b= - 16/3

⇒ b = -16

HOPE IT HELPS YOU:)