17. If A+B+C = 90 , then sin²A + sin²B+ sin²C=
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Answered by
1
From Triangle,
sinA=ABBC; sinB=ABAC
⇒sin2A+sin2B
AB2BC2+AB2AC2=AB2BC2+AC2
From △ABC, by using Pythagoras Theorem,
AB2=BC2+AC2
sin2A+sin2B=AB2BC2+AC2=AB2AB2=
Answered by
2
Answer:
sin²A + sin²B+ sin²C= 1- 2sinAsinBsinC
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