Question

17. If a variable assumes the values 1, 2, 3.... 5 with frequencies as 1, 2, 3,....5 then what is the AM?
(a) 11/3
(b) 5
(c) 4
(d) 4.50
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Answer 1

Step-by-step explanation:

AM

$am = \frac{n1 f1+ n2f2 + n3f3 + n4f4 + n5f5}{f1 + f2 + f3 + f4 + f5}$

$am = \frac{1 \times 1 + 2 \times 2 + 3 \times 3 + 4 \times 4 + 5 \times 5}{1 + 2 + 3 + 4 + 5}$

am

$am = (1 + 4 + 9 + 16 + 25) \div( 1 + 2 + 3 + 4 + 5)$

$am = 55 \div 15$

am=11/3