Question

17. If each edge of a cube is increased by 50% then the percentage surface area increase​

Answer 1

Answer:

Let the original side be a

Then ,

Original surface area S = 6a²

When side is increased by 50%, side becomes

$\frac{3}{2} a$

Then ,

Surface area

$s = \frac{27}{2} {a}^{2}$

Hence,

Surface area is increases by x =

$\frac{\frac{27}{2} {a}^{2} - 6a}{6 {a}^{2} } \times 100 = 125\%$

This is the required solution.

Answer 2

Answer:

the correct answer is 125%