Question

17. If force, time and length are taken as fundamental units then calculate
the dimension of surface tension, power and mass.​

Answer 1

$\Large\bold{\underline{\underline{Answer:-}}}$

Dimensions are:—

1. Surface tension =$\bold{M^1L^0T^{-2}}$
2. Power = $\bold{M^1L^2T^{-3}}$
3. Mass = $\bold{M^1 L^0 T^O}$

→See attachments for derivation

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✦Dimensional Formula or Dimensions refers to a simple formulation which basically represents the various fundamental physical quantities (M, L T etc.) a larger physical quantity depends upon with the help of powers.

✦The dimension of any physical quantity is the combination of the basic physical dimensions that compose it. Some fundamental physical dimensions are length, mass, time, and electric charge. All other physical quantities can be expressed in terms of these fundamental physical dimensions.

Answer 2

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$\boxed{Explained\:Answer}$

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 Density=mass/volume

so if

Mass=F/A

so F/L^-2=mass

therfore it becomes

F^1*L^1*T^-2/F^0*L^3*T^0

F^1*L^-2*T^-2 is the dimensional formula for density when F,L and T are chose as the fundamental quantities