Question

17.
If PR is a straight line find the measure of:
(a) POQ
(b) QOR​

Answer 1

Answer:

Given-

∠ POQ = (3x+10)°

∠ QOR = (7x-30)°

Ray OQ stands on a line PR. Then,

∠POQ+∠QOR = 180° [Linear pair angle]

(3x+10)°+(7x-30)° = 180°

(3x+10+7x-30)° = 180°

10x-20° = 180°

10x = 180°+20°

10x = 200°

x = 200°/10

= 20°

Therefore,

∠ POQ = (3x+10)° = (3×20+10)° = 70°

∠ QOR = (7x-30)° = (7×20-30)° = 110°