17. If sec 5A = cosec (A + 30) where 5A is an acute angle then value of
A is.
(a) 15° (b) 5
(c) 20°
(d) 10°
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Given
sec 5A = cosec ( A + 30 )
{ we know secA = cosec (90 – A) }
cosec ( 90 – 5A ) = cosec ( A + 30 )
Since cosec of both the angles are same therefore angles will also be same
➡ 90 – 5A = A + 30
➡ – 6A = 30 – 90
➡ – 6A = – 60
➡ A = 60 / 6
➡ A = 10
Hence, (d) 10° is the correct answer
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