Question

17. If the mode of a frequency distribution exceeds its median by 8, then the mode
exceeds its mean by
A. 4
B. 12.
C. 6
D. 24
is​

Answer 1

Answer:

The answer will be 12 (option B).

Step-by-step explanation:

Given;

mode = median - 8;

median = mode + 8;

here, we'll use empirical formula, which states,

3 Median = Mode + 2Mean;

Hence,

3 (Mode + 8) = Mode + 2Mean

3Mode + 24 = Mode + 2 Mean

(2Mode + 24)/2 = Mean

Mode + 12 = Mean;

Thus, Mode exceeds Mean by 12.

That's all.

Answer 2

Answer:

hopefully it's helpful to you!!

Step-by-step explanation:

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