17. If the rate of interest is 36/3%p.a. and the difference of the CI and the SI on a sum of money for
3 years is Rs 46 then find the sum of money.
Answers
Answered by
2
Step-by-step explanation:
R=6
3
2
%=
3
20
% per annum
T(n)=3 years
C.I. − S.I. =Rs.46
S.I=
100
PTR
=
3×100
P×3×20
=
10
2P
C.I=P[(1+
100
R
)
n
−1]
C.I=P[(1+
3×100
20
)
3
−1]
C.I=P[(
15
16
)
3
−1]
C.I.=P(
3375
4096
−1)
C.I.=P(
3375
4096−3375
)
C.I.=
3375
721P
According to question,
C.I. − S.I. =46
⇒ P(
3375
721
−
10
2
)=46
⇒ P(
6750
1442−1350
)=46
⇒
6750
92P
=46
⇒ P=
92
46×6750
∴ P=3375
Answered by
1
Answer:
therefore,p=3375
Step-by-step explanation:
Answer is p =3375.
I hope this answer help.
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