Question

17. If velocity of a particle is increased by 60%
then find percentage increases in its K.E.​

Answer 1

let the initial velocity be v

increased velocity =v*60%

=v*60/100

=v*3/5

KE of initial velocity =1/2mv*v

KE of final velocity =1/2m 9/25v*v

change in KE=-9/50mv*v +1/2mv*v

=16/50mv*v

% change=16/50*100

300%