17. In a drawer of shirts, 8 are blue, 6 are green
and 4 are magenta. If Mason draws 2 shirts
at random, what is the probability that at
least one of the shirts he draws will be blue?
Answers
Answered by
0
Answer:
12/17
Step-by-step explanation:
there are a total of 18 shirts. 8 blue and 10 non blue.
P(selecting at least 1 blue shirt) = 1 - P(selecting no blue shirts)
Assuming no replacement
P(selecting first non-blue shirt) = 10/18
P(selecting secong non-blue shirt) = 9/17
P(selecting no blue shirts) = 10/18 * 9/17= 10/34
Therefor P(selecting at least 1 blue shirt) = 1 -(10/34)= 24/34=12/17
Similar questions