17. In right angled triangle ABC right angled at B, P is mid point of AC which one is true? (A) PA = (AB)/2 (B) PA = PB = PC (C) PB = (AC)/4 (D) none of these
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In the adjoining figure, △ABC is right-angled at B and P is the mid-point of AC, show that, PA=PB=PC.
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Solution
GIVEN QP∣∣BC
consider triangles AQP,ABC
angle A= angle A
angle AQP= angle ABC
angle APQ=angle ACB
therefore triangles ABC and AQP are similar
but AP=PC
therefore AP:AC=1:2
therefore AQ:AB=1:2
therefore Q is mid point of AB
now consider triangles AQP,BQ
AQ=BQ
QP=QP
angle AQP=angle BQP
according to SAS axiom AQP congruent to BQP
therefore PA=PB
therefore PA=PB=PC
answer is option b
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