17. In the given fig. PQRS is a rectangle, PQ=11cm,
PS=60cm, then find the value of AB=?
दिए गए आकृति में PQRS एक आयत है। PQ=11cm
और PS=60cm है तो AB का मान ज्ञात कीजिये?
Answers
Answer:
AB = 49 ans
Step-by-step explanation:
PQ = 11 cm
PS = 60 cm
PR = 61 cm because (11,60,61 are triplets)
radius of the circle
r = area / semi perimeter of circle
r = (60x11/2)/(11+60+61)/2
r = 660/132
r = 5
let circle touch PQ at T
then QT = radius of circle
and PT = PQ - QT = 11-5 = 6
and PT = PA .. tangent to the circle from a point.
similarly other circle touch RS at U
then RB also equal to 6
now AB = PR - PA - PB
AB = 61 - 6 - 6
AB = 49 ans
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Given : PQRS IS A REATANGLE PQ= 11CM, PS= 60CM
To Find : VALUE OF AB
Solution:
Let right top circle touching PS at M & SR at N
PB = PM Equal Tangent
SM = SN Equal Tangent
PS = PM + SM = 60
=> PB + SN = 60
RS = RN + SN = 11
RN = RB
=> RB + SN = 11
PB + SN = 60
RB + SN = 11
=> PB - RB = 49
Similarly we can Show that
RA - PA = 49
PA + AB - RB = 49 PB = PA + AB
RB + AB - PA = 49 RA = RB + AB
Adding Both
2AB = 98
=> AB = 49
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