17. In the given figure, AB || CD and EF || GH. Find the values of x, y, z and t.
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Answer:
x=60deg. ( vertically opposite angle)
z = ang RPQ (corresponding angle)
ang RPQ=(180-110)=90
so,
z=90deg.
t=z (alternate angle)
t=90deg.
ang APR= angPRS
110=x+angQRS
110-x=angQRS
angQRS=110-60=50 deg
therefore,
in Triangle QRS
y=(180-t+angQRS)
y=180-90+50)
y= 40 deg.
Answered by
2
x=60deg. ( vertically opposite angle)
z = ang RPQ (corresponding angle)
ang RPQ=(180-110)=90
so,
z=90deg.
t=z (alternate angle)
t=90deg.
ang APR= angPRS
110=x+angQRS
110-x=angQRS
angQRS=110-60=50 deg
therefore,
in Triangle QRS
y=(180-t+angQRS)
y=180-90+50)
y= 40 deg.
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