Question

17. In triangle ABC, right angled at A, AD is drawn perpendicular to BC. If BC = 16 cm and CD = 4 cm, find the length of AC. * 0/1 (a) 4 cm (b) 5 cm (c) 8 cm (d) 3 cm

Answer 1

Answer:

Solution

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm