Math, asked by Anonymous, 1 month ago

17 जून, 1998 को सप्ताह का दिन क्या था?​

Answers

Answered by safnajaleeltk
1

बुधवार

17 जून, 1998 = (1997 वर्ष + 1.1.1998 से 17.6.1998 तक)

1600 वर्षों में विषम दिन = 0

300 वर्षों में विषम दिन = (5 x 3) 1

97 वर्ष में 24 लीप वर्ष + 73 साधारण वर्ष हैं।

97 वर्षों में विषम दिनों की संख्या (24 x 2 + 73) = 121 = 2 विषम दिन।

जनवरी, मार्च अप्रैल मई जून

(३१ + २) + ३१ + ३० + ३१ + १ 31) = १६ 28 दिन

24 168 दिन = 24 सप्ताह = 0 विषम दिन।

विषम दिनों की कुल संख्या = (0 + 1 + 2 + 0) = 3।

बुधवार का दिन है।

Wednesday

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan. Feb. March April May June

(31+28+31+30+31+17) = 168 days

∴ 168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

Answered by NehaHaroon
1

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