Question

17. (k + 1)x2 + 2(k + 3x + (k + 8)=0​

Answer 1

ANSWER-

2k+2+2(k+3x+k+8)=0

2k+2+2(k+3x+k+8)=02k+2+2k+6x+2k+16=0

2k+2+2(k+3x+k+8)=02k+2+2k+6x+2k+16=06k+6x+18=0

2k+2+2(k+3x+k+8)=02k+2+2k+6x+2k+16=06k+6x+18=0k+x+3=0