Question

(17 lt is known that a box of 800 electric bulbs contains 36 defective bulbs
One bulb is taken at random out of the box. What is the probability that
the bulb chosen is nondefective?​

Answer 1

Answer:

P(E)=191÷200

Step-by-step explanation:

n(S)=800

P(E)=n(E)÷n(S)

800-36=764=n(E)

P(E)=764÷800=191÷200

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Answer 2

the bulb that is defective is equal to 800 -36 is equal to 764 den answer will be 764 /800