Question

(17)
P-II
51.
If x = 2^3 x 3^2 x 5^3 x 7^3
y = 2^2 x 3^3 x 5^4 x 7^3, and
z = 2^4 x 3^4 x 5^2 x 7^5,
then H.C.F. of x, y and z is
(1) (15)^3 x 7^4
(2) (30)^3 x 7^3
(3) 30x7^5
(4) (30)^2 x 7^3​

Answer 1

Answer:

(4)30^2x7^3

Step-by-step explanation:

HCF(x,y,z)=2^2x3^2x5^2x7^3

= 4x9x25x7^3

= 30^2 x 7^3