17. Read the following and answer any four questions from 17 0 to 12. (V)
Radhika went to an electronic shop to get her radio repaired. The electrician
required resistances of 3 N and 14 N to repair the radio set. He had a large number
of 4 N resistors. So, he made attempts but could not get the correct combination of 3
N and 14 O resistances. Radhika has studied the combination of resistors and helped
the electrician to arrange the 4A resistors to obtain the required resistances.
O low would Radhika have arranged the 4 A resistors to obtain the 3 N resistance?
Answers
Given : required resistances of 3 N using 4N
To Find : How to achieve
Solution:
Take 3 Resistor
4N resistors ranged in series will be multiple of 4
Required resistance = 3N = 3 * 4N / 4 = 12N / 4
Hence if we add 4 , 12N resistors in parallel , net resistance would be
= 1/(1/12N + 1/12N + 1/12N + 1/12N)
= 12N/4
= 3N
12 N resistance can be achieved by adding 4N resistance 3 times in series .
So to achieve 3N resistance from 4N resistors
12 resistors of 4N are required which will arranged in way
4 Parallel combination of ( 3 series resistors of 4N)
Learn More:
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Step-by-step explanation:
Given : required resistances of 3 N using 4N
To Find : How to achieve
Solution:
Take 3 Resistor
4N resistors ranged in series will be multiple of 4
Required resistance = 3N = 3 * 4N / 4 = 12N / 4
Hence if we add 4 , 12N resistors in parallel , net resistance would be
= 1/(1/12N + 1/12N + 1/12N + 1/12N)
= 12N/4
= 3N
12 N resistance can be achieved by adding 4N resistance 3 times in series .
So to achieve 3N resistance from 4N resistors
12 resistors of 4N are required which will arranged in way
4 Parallel combination of ( 3 series resistors of 4N)
Learn More:
Two resistors of resistance 1.0 Ω and 2.0 Ω connected in parallel are ...
brainly.in/question/18350094
“series combination” and “parallel combination”
brainly.in/question/11390122