Math, asked by kheparvaishali, 12 days ago

17
Read the text prven below and newer any four questions
The following dat geven the weight of 30 ranges picked from a banken
106,107, 76,109,187,95.125.92,70.139.128.10098 84.99,113,204,141.136.123
110.97 90 107,75 30.1182
Tally marks
Frequency
T
3
TO
9
5
1
140-160
160-180
180-200
200-220
Total
1
30
Clasize of given Class data
(a) 20
(bj 10
30 (d) 15
(ii) Classmark of fourth class
(a) 70 (b) 130
A 20 (d) 15
(iii) The number of oranges, whose weight is more than 180g.
1
1
(b) 3
(c 2
(d)
(iv) The number of oranges whose weight is less than 100 g
la) 10 (b) 3
(6) S
13
(s) The range of data is
(b) 204
of 134
(d) 274
18
Read The text given below and answer any four questions:
(in kglare recorded to maintain the health report cards​

Answers

Answered by Anonymous
4

Answer:

Here , class width = 20

class mark = 70

Half of the class width =20 /2  =10

Upper limit of first class interval = 70 + 10 = 80

Lower limit of  first class interval = 70 – 10 = 60

Thus, class interval becomes 60 – 80

So, frequency distribution table

(a) Number of oranges weights more than 180 g = 1 + 1 = 2

(b) Number of oranges weights less than 100 g = 3 + 10 = 13

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