Question

17. Represent Real-World Problems A chemist mixed x milliliters of 25% acid solution with some 15% acid solution to produce 100 milliliters of a 19% acid solution. Use this information to fill in the missing information in the table and answer the questions that follow.  a. What is the relationship between the milliliters of acid in the 25% solution, the milliliters of acid in the 15% solution, and the milliliters of acid in the mixture?​

Answer 1

Answer:

0.25x+0.15(100-x)=19

Answer 2

Answer:

To form 100 milliliters of 19% acid solution, 40 milliliters of 25% acid solution, and 60 milliliters of some 15% acid solution were mixed.

Explanation:

Given that,

25% acid solution contains 'x' milliliters. ie, 0.25x

So, 15% acid solution contains 100-x milliliters. ie, 0.15(100-x)

The total solution is 100 milliliters of a 19% acid solution =

                                                                                 100×.19 = 0.25x+0.15(100-x)

                                                                                          19 = 0.25x+15-0.15x

                                                                                            4 = 0.10x

                                                                                             x = 40

So, 100 milliliters of 19% acid solution, 40 milliliters of 25% acid solution, and 60 milliliters of some 15% acid solution were mixed.