Question

17.
See the arrangement shown in figure. If the acceleration of block B is a, then
the acceleration of block A in magnitude will be:
(B) 2a
(A) a
(C)3a
(D) 4a​

Answer 1

Answer:

Hyy mate

Free body diagrams for two mass blocks and two pulleys are given in figure.

Force balance equations for all the cases are given below

For m1 :-

For m2 :-

for pulley P1 :- 2×T - T = 0 × aP1 ......................... (3)

for pulley P2 :- T2 - 2×T = 0 × aP2 .....................(4)

By solving Eqns. (1), (2), (3) and (4) , we get a1 = - g and a2 = g

Hence both blocks are moving downwards with acceleration g m/s2