Question

17. Show that (p-1) is a factor of (p^10 – 1) and also of (p11 - 1).​

Answer 1

Answer:

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Step-by-step explanation:

1 Answer. and h(p) = p11 -1. g(1)=110-1= 1-1=0 Hence, p-1 is a factor of g(p). h (1) = (1)11 -1 = 1 -1 = 0 Hence, p -1 is a factor of h(p).Jan 30,

Answer 2

(p-1)=0

p=1

now

put this value in the following equations.

note

if after p=1 . the value became zero .then it Isa factor of the following equation .....

ATQ

• P¹⁰-1

1¹⁰-1

1-1

0

YES, (p-1) IS A FACTOR of p¹⁰-1

• p¹¹-1

1¹¹-1

1-1

0

YES,, (p-1) IS A FACTOR of p¹¹-1