Question

17) Show that the points A (1, 2), B (– 1, – 16) and C (0, – 7) lie on the graph of the linear equation y = 9x – 7.

Answer 1

Your Answer:

• $\tt Linear \ \ Equation \rightarrow y=9x-7$

• $\tt Coordinates \rightarrow A(1,2) , \ \ B(-1,-1) \ \ and \ \ C(0,-7)$

If we put the value of x in the Equation, and if we get the correct value of y, then it will be proved that the points lie on same coordinate.

In case 1,

Where the point is (1,2)

So, x = 1 and y = 2

Putting value of x in the Equation

$\tt y = 9(1) - 7 \\\\ \tty = 9 -7 \\\\ \tt y = 2$

Hence this point lies on the graph of linear Equation y = 9x - 7

In Case 2,

Where the point is (-1,-16)

So, x = -1 and y = -16

Putting value of x in the Equation

$\tt y = 9(-1) - 7 \\\\ \tt y = -9 -7 \\\\ \tt y = -16$

Hence this point lies on the graph of linear Equation y = 9x - 7

In Case 3,

Where the point is (0,-7)

So, x = 0 and y = -7

Putting value of x in the Equation

$\tt y = 9(0) - 7 \\\\ \tt y = 0 -7 \\\\ \tt y = -7$

Hence this point lies on the graph of linear Equation y = 9x - 7

Hence all the points lie on the Graph of linear Equation y = 9x - 7

Proved

Answer 2

Step-by-step explanation:

7=−16

For C(0,−7), we have - 7=9(0)−7=0−7=−7

We see that the line y=9x−7 is satisfied by the points A(1,2),B(−1,−16) and C(0,−7).

Therefore, A(1,2),B(−1,−16) and C(0,−7) are solutions of the linear equation y=9x−7 and therefore, lie on the graph of the linear equation y=9x−7.