Math, asked by adityashukla1432006, 5 months ago

17. Sixteen cards are labelled as a, b, c, ..., m, n, o, p. They are put in a box and shuffled. A
boy is asked to draw a card from the box. What is the probability that the card drawn
is:
(1) a vowel
(ii) a consonant
(iii) none of the letters of the word median.
(2017)​

Answers

Answered by Anonymous
18

Answer:

hope it helps you...........

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Answered by Choudharipawan123456
0

Answer:

Hence, the required probability -

(1) \frac{1}{4} \\\\(2) \frac{3}{4}\\\\(3) \frac{5}{8}

Step-by-step explanation:

In context to questions asked,

We have to determine the probability that the card is drawn,

It is given that,

16 cards are labeled as $ {a, b, c, ..., m, n, o, p} $

They are shuffled and placed in a box.

Outcomes: a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p

Total number of all possible outcomes 16

( 1 ) The possible outcomes are a, e, i, o

Number of favorable outcomes 4

Therefore,

Required probability

$=\frac{4}{16}=\frac{1}{4}$

( 2 ) Number of favorable outcomes

$16-4=12$

Therefore,

Required probability

$=\frac{12}{16}=\frac{3}{4}$

( 3 ) The possible outcomes are b, c, f, g, h, j, k, l, o, p.

Number of favorable outcomes 10

Therefore,

Required probability

$=\frac{10}{16}=\frac{5}{8}$

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