Question

17. Solve this problem
​

Answer 1

Answer:

a + b + c =16

Step-by-step explanation:

(a+b+c)²=a ²+b²+c²+2(ab+bc+ca)

(a+b+c)²=200+2(28)

(a+b+c)²=200+56

(a+b+c)²=256

a+b+c= root of 256

a+b+c= 16

hope it helps you...

Answer 2

Identity to be used:

(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)

Put values:-

(a+b+c)^2 = 200 + 2(28)

(a+b+c)^2 = 200 + 56

a + b + c = √256

a + b + c = ±16