Question

17. Solve x - y = 3 and 2x + 3y = 6 by substitution method​

Answer 1

Answer :

• x = 3
• y = 0

Step-by-step explanation :

Given equations,

• x - y = 3 -- [1]
• 2x + 3y = 6 -- [2]

Substitution method :

From equation [1],

⇾   x - y = 3

⇾   x = y + 3

Substitute x = y + 3 in equation [2],

   2x + 3y = 6

2(y + 3) + 3y = 6

2y + 6 + 3y = 6

 5y + 6 = 6

 5y = 6 - 6

 5y = 0

 y = 0/5

 y = 0

Substitute y = 0,

x = y + 3

x = 0 + 3

x = 3

Therefore, x = 3 and y = 0

Verification :

• x = 3
• y = 0

Substitute in equation [1],

x - y = 3

3 - 0 = 3

 3 = 3

LHS = RHS

Substitute in equation [2],

2x + 3y = 6

2(3) + 3(0) = 6

6 + 0 = 6

 6 = 6

 LHS = RHS

Hence verified!

Answer 2

SoLuTiOn:-

$\huge\sf\red{Given}$

$\sf\purple{x-y=3}$ ____1

$\sf\orange{2x+3y=6}$___2

We have to solve by substuition method So take eq 1

$\sf\pink{x-y=3}$

$\sf\blue{x = y+3}$

So substuite value of x in eq 2

Entire equation converting interms of y

$\sf\green{2(y+3)+3y=6}$

2y+6+3y=6

5y + 6 = 6

5y = 0

$\sf\purple{y=0}$

Substuite value of y in eq 1

$\sf\pink{x-y=3}$

x-0 = 3

$\sf\purple{x = 3}$

$\sf\red{Values of x,y = 3,0}$