Question

17. Sumitra has 34 in 50-paise and 25-paise coins. If the number of 25-paise coins is twice
the number of 50-paise coins, how many coins of each kind does she have?​

Answer 1

Answer:

Sumitra has 34 in 50-paise and 25-paise coins.

$0.5x + 0.25y = 34$

If the number of 25-paise coins is twice the number of 50-paise coins,

$y = 2x$

So,

$0.5x + 0.25y = 34 \\ 0.5x + 0.25 \times 2x = 34 \\ 0.5x + 0.5x = 34 \\ x = 34 \\ and \\ y = 2x = 68$

So, total number of coins

$x + y = 34 + 68 = 102$