17 term of an ap exceeds its 10th term by 7 find the common difference
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Answered by
3
Answer:
common difference = 1.
Step-by-step explanation:
Let a be the first term of the AP and d be the common difference.
i.e. the series becomes a, a +d, a+2d.....
Now formula for nth term of an AP, tₙ = a + (n - 1)d.
10th term is t₁₀ = a + (10 - 1)d = a + 9d.
17th term is t₁₇ = a + (17 - 1)d = a + 16d.
Now given t₁₇ - t₁₀ = 7.
=> a+16d - (a + 9d) = 7
=> a + 16d - a - 9d = 7
=> 7d = 7
=> d = 1
The common difference of given AP is 1.
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Answered by
2
Answer:
let a be the first term and d be the comman difference
a17 = a10 +7
a+16 d = a+9d +7
a +16d- a-9d =7
7d =7
d=1
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