Question

17. The area of A ABC is 90 cm2. If BC = 15 cm, find the height AM.​

Answer 1

Answer:

12cm

Step-by-step explanation:

Area = 90cm

length = 15cm

height = x

$90 = \frac{1}{2} \times x \times 15 \\ \\ 90 = \frac{15}{2} x \\ \\ 90 \times 2 = 15x \\ \\ 180 = 15x \\ \\ \frac{180}{15} = x \\ \\ 12 = x$

Hence,12cm is height.

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Answer 2

Answer:

Height AM= 12 cm

Step-by-step explanation:

Given,

The area of ΔABC = 90 $cm^{2}$

BC= 15cm

To find AM.

Let us construct a Triangle and represent the given information.

The height AM is perpendicular to the Base BC

hence, area of  ΔABC= $\frac{1}{2} \times (base) \times height$

 90 = $\frac{1}{2} ( BC \times AM)$

180 = 15 × AM

AM= $\frac{180}{15}$

∴ AM= 12 cm

The Perpendicular height (AM) with respective base (BC) is 12 cm