Question

17. The area of a rectangular plot is 460 m2. If the length is 15% more than its breadth,
find the perimeter of the plot.​

Answer 1

Given:-

=>Area of rectangular plot =460m²

=>Length of the plot is 15% more than it's breadth.

To find:-

=>Perimeter of the plot

Solution:-

=>Let the breadth of the plot be x

=>Then,length of the plot=15% of x

=>15x/100

=>3x/20

=>x+3x/20

=>23x/20

=>Area of a rectangle=Length×Breadth

=>23x/20×x=460

=>23x²/20=460

=>x²=460×20/23

=>x²=400

=>x=20

=>Thus,breadth of the plot is 20m

=>And length=23×20/20=23m

=>Perimeter of a rectangle=2(l+b)

=>2(20+23)

=>2×43

=>86m

Thus,perimeter of the plot is 86m.

Mark me Brainliest!!

Answer 2

Answer:

20 meter

Step-by-step explanation:

We know that the area of a rectangle is the product of length and breadth. Thus,

Area A of the rectangular plot = Length x Beadth …………………………………….(1)

Given, length is 15% more than the breadth.

That is, Length = Breadth + (15/100) breadth

= Breadth + .15 x Breadth = (1.15)Breadth

∴ A = 1.15 x Breadth x Breadth = 1.15 x (Breadth)² ………………………………….…(2)

Given, A = 460 square meters

Substituting in (2),

460 = 1.15 (Breadth)²

Or, 460/1.15 = 1.(Breadth)² [Dividing both sides by 1.15]

Or, (Breadth)² = 460/1.5 = 400 = 20² square meter

Taking square root,

Breadth = ±20 meter

Since length is always a positive quantity, we discard the negative value to get

Breadth = 20 meter

please mark THIS ANSWER AS BRAINLIEST