Question

17. The area of an isosceles right angled triangle with 12 cm as its equal sides is​

Answer 1

GIVEN :-

• Equal sides of isosceles triangle are 12 cm each .

• Triangle is Right angled Triangle

TO FIND :-

• Area of triangle.

SOLUTION :-

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▪︎Area of triangle = 1/2( base × height)

= 1/2 (12 cm × 12 cm)

= 1/2(144 cm²)

= 1/2 × 144 cm²

= 72 cm²

Hence Area of isosceles right angle triangle is 72 cm²

ADDITIONAL INFORMATION :-

▪︎Area of triangle = 1/2(base × height)

▪︎Area of equilateral triangle = (√3a²/4)

▪︎properties of triangle:-

• Angle sum property of triangle
• Exterior angle property
• Interior angle property

Answer 2

Given ,

The side of isosceles right angled triangle is 12 cm

We know that , the area of right angled triangle is given by

$\large \sf \star \: \: \fbox{Area = \frac{1}{2} \times base \times height}$

Thus ,

$\sf \mapsto Area = \frac{1}{2} \times 12 \times 12 \\ \\\sf \mapsto Area = \frac{144}{2} \\ \\\sf \mapsto Area = 72 \: \: {cm}^{2}$

$\therefore \sf \underline{The \: area \: of \: isosceles \: right \: angled \: triangle \: is \: 72 \: {cm}^{2} }$